A student wants to use CPM to analyze the schedule: a) Show all potential paths
ID: 432331 • Letter: A
Question
A student wants to use CPM to analyze the schedule:
a) Show all potential paths and their durations.
b) What is the critical path?
c) How long is the project duration?
d) If activity “a” does not start until the second day (delayed by one day), what is your new estimate on total project duration?
e) If activity “e” does not finish until day 10 (delayed by one day), what is your new estimate on total project duration?
Question 2:
Consider a project having the following seven activities:
a) What is the expected project completion time?
b) What is the most economical way and how much will it cost to reduce the completion time of the project by three weeks?
c) What is the most economical way and how much will it cost to reduce the completion time of the project by three weeks?
Please show all work, explanations, and label each answer with their corresponding question. Thank you
Immediate Activity Pred. fb.c,Explanation / Answer
PLEASE FIND BELOW ANSWER TO QUESTION # 1 :
a-b-f = 3 + 4 + 7 = 14 days
a-c-f = 3 + 5 + 7 + 15 days
d-e-f = 3 + 6 + 7 = 16 days
Therefore , project duration is 16 days
Slack is the amount of maximum duration upto which an activity may get delayed and yet the project completion date does not get affected.
Since slack of activity a is 1 day, it means project duration will not get affected if activity a gets delayed by 1 day maximum.
Therefore new estimate of project duration ( remarks : duration remains unchanged ) = 16 days
Activity e lies on critical path and therefore has zero slack.
Thus, if activity e gets delayed by 1 day, project completion also gets delayed by 1 day .
Therefore , revised projectduration = 16 + 1 = 17 days
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