A student used a cation exchange resin to determine the molarity of sodium ion i

Question

A student used a cation exchange resin to determine the molarity of sodium ion in an unknown sodium chloride solution. The student diluted a 24 mL aliquot of the original unknown solution to 250.0 mL in a volumetric flask. After passing a 50.00 mL aliquot of the dilute unknown sodium chloride solution through a cation exchange resin, 30.00 mL of 0.010 M sodium hydroxide solution were required to titrate the eluate. Calculate the Molarity of sodium ion in the original sodium chloride solution in unit of mol/L. (pay attention to the sig.fig. in your calculation. Keep two sig.fig. in the answer.)

Explanation / Answer

use Titration formula:
M1*V1 = M2*V2
1 is for NaCl and 2 is for NaOH
M*50 = 0.01*30
M = 6.0*10^-3 mol/L
Answer: 6.0*10^-3 mol/L

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