Explain please. I have included the answer. Please show how to get the answer. T
ID: 43089 • Letter: E
Question
Explain please. I have included the answer. Please show how to get the answer. Thanks!
A new kind of tulip is produced that develops only purple or pink flowers. Assume that flower color is controlled by a single-gene locus, and that the purple allele (C) is dominant to the pink allele (c). A random sample of 1000 tulips from a large cultivated field yields 847 purple flowers, and 153 pink flowers.
a. Determine the frequency of the purple and pink alleles in this field population.
b. Estimate the proportion of all purple flowering plants that are heterozygotes and homozygotes.
ANSWER:
a. purple allele (C) = 0.609, pink allele (c) = 0.391
b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476
Explanation / Answer
A)
We will asume that the popullatuon is in hardy - weinberg equilibriam
p2 + 2pq + q2 = 1
let P be the dominant purple allele C
and , q be the recessive allele c
apllied the hardy winsberg equation
Frequency of pink allele = q2 = 153 / 1000 = 0.153
and ,
q = (0.153)1/2 = .39
because p+q= 1
therefore p= 1-q = .61
purple allele frequency = 0.61 (been rounded of your answer)
pink allele frequency = 0.39 (same here)
2)
if popullation in hardy - weinberg equilibriam
p2 + 2pq + q2 = 1
For heterozygote 2pq = 2( 0.61)(0.39) = 0.476
Therefore ,
(0.476)(1000) or 47.6% = 476
Purple flowered plant expected to be heterozygote Cc = 476
consequentaly
(p)2(1000) = (0.61)2 (1000) = 372
Purple flowered plant expected to be homozygous CC = 372
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