PLEASE HELP WITH C!!! :( Question Help Problem 15 1-8 Q systern, th\" dernrd ral

Question

PLEASE HELP WITH C!!! :(

Question Help Problem 15 1-8 Q systern, th" dernrd rale for straw e ? ?" rsam normal distributed, with an 8 er e o 2 5 prts per week The lead tame s e a eek. The stand8rd dev ien of weed y demand s 18 p ts Refer to thegt nder a. The siandard doviation of domand during the 6 wook load timo is 39 pints. (Enter your rospanse roundcd to tho noarost wholo numborJ b. The avorage demand during the 6-weak lead tme is 1,770 pins (Emer your responso aa n intogor) c. Thereo der port that results n 8 ?? cle-ser ce level of 90 percentis pits Enter your response rounded to tre nearest whole number o m t fr z values Data Table Tho tabio bolow shows the tota aroa under tho normal cure for a point that is Z standard doviations to tho rght of the mesn 08079 0.8106 0.8133 09850 0.9854 0.9857 22 0.9061 095 0.00.9071 08 9087 0.989 23 0.9033 0 6.9999 0 9901 09604 0.9906 0.9994 Enter your answer in the answer box and then click Check Answer. 33 0.999 0960.999509996 086 0.8996 0.9996 0 0.9996 0.9997 Check Answer

Explanation / Answer

Z value for 90% service level = NORMSINV ( 0.90 ) = 1.2815

Standard deviation of demand during 6 week lead time = 39 pints

Therefore , Safety stock

= Z value x standard deviation of demand during lead time

= 1.2815 x 39

= 49.9785 ( 50 rounded to nearest whole number )

Thus,

Reorder point for a cycle service level of 90 percent

= average demand during lead time + Safety stock

= 1770 + 50

= 1820

THE REORDER POINT = 1820 PINTS

THE REORDER POINT = 1820 PINTS

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