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ore: 0 of 6 pts roblem 16.16 he partially completed inventory record for the dri

ID: 423608 • Letter: O

Question

ore: 0 of 6 pts roblem 16.16 he partially completed inventory record for the driveshaft subassembly in the table below shows gross requirements, scheduled receipts, lead Sme, and current on-hand inventory ?Complete the last three rows ofthe record for an FOQ of 50 units. (Enter yourosponses as mogen Aresponse of O'segment to begndapa? 20f 340 complete) ? HW Score: 09%, 0 of 24p Question Help Lot Size: FOO 50 units Lead Time: 3 weeks Item: Driveshaft subassembly Week Gross 30 30 20 25 30 30 40 40 Scheduled rece pts Projected on-hand inventory Planned receipts 75

Explanation / Answer

Formulas:

Net requirement = GR of week – projected on-hand of previous week – Scheduled Receipts of week

Projected on-hand (POH) = Projected on-hand of previous week + SR of week – GR of week + Planned order receipt (PORc) of week

Planned order receipt = if the project-on-hand is negative, place an order of 50 units.

In week 4, the POH = 10 + 0 – 25 = -15, thus there is requirement of 15 units in week 4, so place the order of 50 units. But since the order size is more than requirement, the inventory =-on-hand will be 50 + 10 – 25 = 35

-1

1

2

3

4

5

6

7

Gross Req.

30

30

20

25

30

30

40

Scheduled receipts

75

0

0

0

0

0

0

Projected-on-hand inventory

(BI= 15

15

75+15-30

= 60

60-30

= 30

30-10

= 10

50+10-25

= 35

35-5

= 5

50+5-30

= 25

50+25-40

= 35

Net Requirement

0

0

0

25-10

= 15

0

30-5

= 25

40-25

= 15

Planned order Receipts

0

0

0

50

0

50

50

-1

1

2

3

4

5

6

7

Gross Req.

30

30

20

25

30

30

40

Scheduled receipts

75

0

0

0

0

0

0

Projected-on-hand inventory

(BI= 15

15

75+15-30

= 60

60-30

= 30

30-10

= 10

50+10-25

= 35

35-5

= 5

50+5-30

= 25

50+25-40

= 35

Net Requirement

0

0

0

25-10

= 15

0

30-5

= 25

40-25

= 15

Planned order Receipts

0

0

0

50

0

50

50