The results of a recent poll on the preference of voters regarding presidential
ID: 422101 • Letter: T
Question
The results of a recent poll on the preference of voters regarding presidential candidates are shown below. Candidate Voters Surveyed Voters Favoring This Candidate A 400 192 B 450 225 ? Using ? = .05, conduct a hypothesis test to determine whether or not there is a significant difference between the preferences for the two candidates.
A- The computed test statistic is _____________which has a p-value of___________
B- Will you reject the null hypothesis? Include yes or no in your response.
C- Is there sufficient evidence to conclude that there is a significant difference between the preferences for the two candidates? Include yes or no in your response.
Note: Use the probability distribution tables to find your p-values. If possible, report the exact p-value (to four decimal places). If an exact p-value is not available, report the smallest possible range for the p-value, using the following format when you report your answer: between lower limit p-value and upper limit p-value For example, enter into the answer box: between .01 and .02 (But report your p-values.)
Explanation / Answer
For Candidate A,
n1 = 400
y1 = 192
p1 (Proportion of voters voted for Candidate A) = 192/400 = 0.48
For Candidate B,
n1 = 450
y1 = 225
p2 (Proportion of voters voted for Candidate B) = 225/450 = 0.5
Overall Sample population = (192+225) / (400+450) = 0.4906 (approx.)
The Test statistic for testing is
H0 : p1=p2 versus H0 : p1 not = p2
Z = (p1-p2) / sqrt( p(1-p) (1/n1 + 1/n2) )
=> Z = -0.0583 - Ans 1
Now, considering Degree of freedom = 1, significance level = 0.05 with the above Z value
Gives us the p-value = 0.481464 which is greater than the significance level. - Ans 1
So, No we don't reject the null hypothesis, instead accept it. - Ans 2
So, we can conclude that there is not very significant difference between the preferences for the two candidates as p1 is equivalent to p2. - Ans 3
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