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At Isogen Pharmaceuticals, the filling process for its asthma inhaler is set to

ID: 410189 • Letter: A

Question

At Isogen Pharmaceuticals, the filling process for its asthma inhaler is set to dispense 150 milliliters (ml) of steroid solution per container. The average range for a sample of 6 containers is 6 ml. Use the accompanying table to establish control limits for sample means and ranges for the filling process.

The UCL Upper RUCLR equals ____ ml and the LCL Subscript Upper RLCLR equals ____ ml. (rounded to two decimal places.)

The UCL UCLx equals _____ ml and the LCLLCLx equals ____ ml. (rounded to two decimal places.)

Explanation / Answer

To be Calculated:

a) Upper Control Limit of Range Chart, UCL-R

b) Lower Control Limit of Range Chart, LCL-R

c) Upper Control Limit of X-bar Chart, UCL-X

d) Lower Control Limit of X-bar Chart, LCL-X

Given Values:

a) Average of X, X-bar = 150 ml.

b) Average of Ranges, R-bar = 6 ml.

c) Number of Samples, N = 6 containers

Solution:

a) Upper Control Limit of Range Chart, UCL-R can be calculated as;

UCL-R = (D4 x R-bar)

Using, the accompanying table, control limits can be established as;

D4 (for N = 6) = 2.004

UCL-R = 2.004 x 6 = 12.024

UCL-R = 12.02 ml.

b) Lower Control Limit of Range Chart, LCL-R can be calculated as;

LCL-R = (D3 x R-bar)

Using, the accompanying table, control limits can be established as;

D3 (for N = 6) = 0

LCL-R = 0 x 6 = 0

LCL-R = 0 ml.

c) Upper Control Limit of X-bar Chart, UCL-X can be calculated as;

UCL-X = X-bar + (A2 x R-bar)

Using, the accompanying table, control limits can be established as;

A2 (for N = 6) = 0.483

UCL-X = 150 + (0.483 x 6) = 150 + 2.898 = 152.898

UCL-X = 152.90 ml.

d) Lower Control Limit of X-bar Chart, LCL-X can be calculated as;

LCL-X = X-bar - (A2 x R-bar)

Using, the accompanying table, control limits can be established as;

A2 (for N = 6) = 0.483

LCL-X = 150 - (0.483 x 6) = 150 - 2.898 = 147.102

LCL-X = 147.10

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