Question 2 (10 pts): The chemical reaction equation of aerobic oxidation of carb

Question

Question 2 (10 pts): The chemical reaction equation of aerobic oxidation of carbohydrate (CH2O) and growth of new bacterial cells (C5H7NO2) can be written as and the oxidation of CH2O to carbon dioxide (CO2) can be written as What is the biomass yield (Y) in terms of g cell/g carbohydrate? What is the biomass yield in terms of g cell/g COD of carbohydrate? What is the oxygen requirement for removing each gram of COD of carbohydrate? (express your results in terms of g O2/g COD carbohydrate removed).

Explanation / Answer

BIOMASS YIELD ;

it is the ratio of biomass produced to the amount of substrate consumed ,it is extensivley , electron donor

biomass yield in terms of COD of carbohydrate ;and biomass yeild of carbohydrate and oxygen rquirements for removing each gram of cod of carbohydrate ;

COD is the chemical oxygen demand of the carbohydrate usually caluculated by the measure of avilability of elctrons of various compounds. COD of carbondioxide can be zero , as the carbon wil be in oxidized state . thus we can caluculate the mass value of each compound which undergoes a change in oxidation state .the total number of moles of any given element in the reactants equals the number of moles of products .COD of oxygen represents the loss of oxygen

by taking the above equation we should caluculate the molecular masses of each molecule oxidized and reduced state ;

molecular mass ;

CH2o = 30 , O2 = 32, NH4 -18, HCO3- 61, c5h7o2n-113, CO2is 44 , water = 18

CH20 +0.290 o2+0.085NH+0.289HC0 3 gives 0.535 C5H2ON +0.633CO2+0.151H2o

from the equation gives the COD

sum of the reacttants =sum of the products ,

so the biomass yeild is about  b0.535g/carbohydrate

0.309 g of oxygen required per g/carbohydrate

now coverstion into COD values ie.,

CH20 + {0.209}O2 gives 0.71 C5H7O2N COD

so the final CODvalues are

0.71 g / carbohydrate of biomas yeild

0.209 oxygen / g of carbohydrate are used to synthesize the biomass

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