QUESTION 1 (Arrival Time) The arrival rate of a retail store is 7 customers (i.e
ID: 396696 • Letter: Q
Question
QUESTION 1
(Arrival Time) The arrival rate of a retail store is 7 customers (i.e., 7 customers arrive on average) per hour. Find the average arrival time.
(a) Customers arrive in an average of ___ hours. [Answer format: three decimal places] (Hint: time = 1/rate, rate = 1/time)
(b) Customers arrive in an average of ___ minutes. [Answer format: one decimal place] (Hint: 1 hour is 60 minutes.) (Note: To avoid rounding errors, use exactly the same arrival time in (a).)
(Note: When calculations in Excel carry rounding errors, calculators are recommended.)
Write your answer(s) as 1.234, 5.6
1 points
QUESTION 2
1 points
QUESTION 3
(Percentages of Types) A supermarket collected counts of customer complaints according to their types as below.
95
54
10
6
(a) The total number of counts is ___. [Answer format: integer]
(b) The percentage of complaints on out-of-stock is ___ % . [Answer format: integer] (Hint: Divide 95 by the total number of counts in (a).)
(c) The percentage of complaints on store conditions is ___ % . [Answer format: integer]
(d) The percentage of complaints on long waiting lines is ___ % . [Answer format: integer]
(e) The percentage of complaints on pricing is ___ % . [Answer format: integer]
(Note: Be careful about rounding errors in (b), (c), (d) and (e). Answers for these questions are percentages. For example, 0.016 is 2% and 0.014 is 1%.)
Write your answer(s) as 123, 45, 67, 8, 9
1 points
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Type of complaints #counts Out of stock95
Store conditions54
Long waiting lines10
Pricing6
Explanation / Answer
1. Arrival rate = lambda = 7 customers per hour
A. Average arrival time
1/lambda = 1/7 = 0.143 hour
B. Average Arrival in minutes = 60*0.143 = 8.58 minutes.
3.
(a) Total Number of counts = 95+54+10+6 = 165
(b) percentage of complaints, out of stock % = (95/165)X 100 = 58 %
C. Percentage on store = (54/165)X 100 = 33 %
(d) percentage of long waiting = (10/165)X 100 = 6 %
(e) percentage of pricing = (6/165)X 100 = 4 %
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