An example of a game in progress 1A21 1 Assignment Your assignment will not invo

Question

An example of a game in progress 1A21 1 Assignment Your assignment will not involve any game playing but you will be required to generate the underlying grid for a game of minesweeper. Your program should read three input values. The first two, m and n represent the dimensions. The game will be played on an m by n board. The third input, p, is a double value between 0 and 1 which represents the probability that a cell contains a mine. (Make sure you validate this input value) Your program should first produce an m by n grid where 1 indicates the presence of a mine and 0 indicate s a safe cell. For each cell, you should generate a random value between 0 and 1. If the value is less than p, you should place a mine in that cell. You should output this grid using an asterisk to indicate the presence of a bomb and a dot to indicate a safe cell. For example, if m 5, n 10 and p 0.3 the output could be as follows (it may differ depending on the random numbers generated):

Explanation / Answer

#include <stdio.h>
#include <time.h>
#include <stdlib.h>

int nextBool(double probability)
{
    return (rand() / (double)RAND_MAX) < probability;
}

char a[50][50];
int b[50][50];
int main(void) {
   srand(time(NULL));
   int m,n;
   double p;
   scanf("%d%d%lf",&m,&n,&p);
   for(int i=0;i<m+2;i++)
   for(int j=0;j<n+2;j++) {
       a[i][j]='.';
       b[i][j]=0;
   }
   for(int i=1;i<m+1;i++) {
       for(int j=1;j<n+1;j++) {
           int k = nextBool(p);
           if(k==1) {
               a[i][j]='`';
           } else {
               a[i][j]='.';
           }
       }
   }
   for(int i=1;i<m+1;i++) {
       for(int j=1;j<n+1;j++) {
           if(a[i][j]=='.')
           {
               if(a[i-1][j-1]=='`')
                   b[i][j]++;
               else if(a[i-1][j]=='`')
                   b[i][j]++;
               else if(a[i-1][j+1]=='`')
                   b[i][j]++;
               else if(a[i][j-1]=='`')
                   b[i][j]++;
               else if(a[i][j+1]=='`')
                   b[i][j]++;
               else if(a[i+1][j-1]=='`')
                   b[i][j]++;
               else if(a[i+1][j]=='`')
                   b[i][j]++;
               else if(a[i+1][j+1]=='`')
                   b[i][j]++;
           }
       }
   }
   for(int i=1;i<m+1;i++) {
   for(int j=1;j<n+1;j++) {
       if(a[i][j]=='.') {
           printf("%d",b[i][j]);
       } else {
           printf("*");
       }
   }   printf(" ");
   }
   return 0;
}

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