-Write a new version of the code below that uses a dictionary instead of if stat

Question

-Write a new version of the code below that uses a dictionary instead of if statements. (USING PYTHON)

def main() :

value = int(input("Please enter a positive integer < 1000: "))
print(intName(value))

## Turns a number into its English name.
# @param number a positive integer < 1,000
# @return the name of the number (e.g. "two hundred seventy four")
#
def intName(number) :
part = number # The part that still needs to be converted.
name = "" # The name of the number.

if part >= 100 :
name = digitName(part // 100) + " hundred"
part = part % 100

if part >= 20 :
name = name + " " + tensName(part)
part = part % 10
elif part >= 10 :
name = name + " " + teenName(part)
part = 0

if part > 0 :
name = name + " " + digitName(part)

return name

## Turns a digit into its English name.
# @param digit an integer between 1 and 9
# @return the name of digit ("one" ... "nine")
#
def digitName(digit) :
if digit == 1 : return "one"
if digit == 2 : return "two"
if digit == 3 : return "three"
if digit == 4 : return "four"
if digit == 5 : return "five"
if digit == 6 : return "six"
if digit == 7 : return "seven"
if digit == 8 : return "eight"
if digit == 9 : return "nine"
return ""

## Turns a number between 10 and 19 into its English name.
# @param number an integer between 10 and 19
# @return the name of the given number ("ten" ... "nineteen")
#
def teenName(number) :
if number == 10 : return "ten"
if number == 11 : return "eleven"
if number == 12 : return "twelve"
if number == 13 : return "thirteen"
if number == 14 : return "fourteen"
if number == 15 : return "fifteen"
if number == 16 : return "sixteen"
if number == 17 : return "seventeen"
if number == 18 : return "eighteen"
if number == 19 : return "nineteen"
return ""

## Gives the name of the tens part of a number between 20 and 99.
# @param number an integer between 20 and 99
# @return the name of the tens part of the number ("twenty" ... "ninety")
#
def tensName(number) :
if number >= 90 : return "ninety"
if number >= 80 : return "eighty"
if number >= 70 : return "seventy"
if number >= 60 : return "sixty"
if number >= 50 : return "fifty"
if number >= 40 : return "forty"
if number >= 30 : return "thirty"
if number >= 20 : return "twenty"
return ""

# Start the program.
main()

Explanation / Answer

def main() : value = int(input("Please enter a positive integer < 1000: ")) print(intName(value)) ## Turns a number into its English name. # @param number a positive integer < 1,000 # @return the name of the number (e.g. "two hundred seventy four") # def intName(number) : part = number # The part that still needs to be converted. name = "" # The name of the number. if part >= 100 : name = digitName(part // 100) + " hundred" part = part % 100 if part >= 20 : name = name + " " + tensName(part) part = part % 10 elif part >= 10 : name = name + " " + teenName(part) part = 0 if part > 0 : name = name + " " + digitName(part) return name ## Turns a digit into its English name. # @param digit an integer between 1 and 9 # @return the name of digit ("one" ... "nine") # def digitName(digit) : if 1 = 60 : return "sixty" if number >= 50 : return "fifty" if number >= 40 : return "forty" if number >= 30 : return "thirty" if number >= 20 : return "twenty" return "" # Start the program. main()

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