Specifications for a part for a DVD player state that the part should weigh betw

Question

Specifications for a part for a DVD player state that the part should weigh between 25.2 and 262 ounces. The process that produces the parts has a mean of 25.7 ounces and a standard deviation of 25 ounce. The distribution of output is normal. Use Table A a.What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the "%" sign in your response.) Percentage of parts 1% b.Within what values will 95.44 percent of sarmple means of this process fall,if samples of n 8 are taken and the process is in control (random)? (Round your answers to 2 decimal places.) Lower valueUpper value

Explanation / Answer

a-

=25.7 ounces

= 0.25 ounce

P(25.2<x26.2)

P(25.2-25.7)/.25 <z < (26.2-25.7)/0.2

P(-2.5 < z < 2.5)

p(z<--2.5) = 0.9938

p(z<2.5)= 0.0062

P(25.2<x26.2) = 0.9876

P(Not neet weight spec)=0.0124

B-

= 25.7 ounces

= 0.25 ounces

n= 8

Mean +/- 2(st dev/sqrt(n))

25.7+/- 2 (.25/ 2.82)

25.7 +/- .18

25.52 to 25.88

Lower value = 25.52

Upper value = 25.88

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