1.Following code will result in: int num = 5/0; Compilation error: Divisions mus

Question

1.Following code will result in: int num = 5/0;

Compilation error: Divisions must be in a try block

2. Assume a, b, and c have been defined to be integer variables. Which of the following values make the expression !(a == b) && (c > a) true?

a = 10, b = 20, c = 10

3.The scope of the parameter is limited to the method which calls it.

False

4.What is printed by the following code fragment?

int[] a = {0,1,2,3,4,5,6};

System.out.println(a.length);

Can't tell. There is not enough information

5.You want to initialize all of the elements of a double array a to the same value equal to 1.5.

What could you write?

.Assume that the array has been correctly initialized)

for (int i=0; i<a.length+1; i++) a[i] = 1.5;

6.Consider the method castToIntArray that has an array of double type as a formal parameter and returns an array of integers. What is the signature of the method?

Explanation / Answer

1.

int num = 5/0;

Runtime Exception: DivideByZeroException.

Option a

2.

a = 10, b = 20, c = 15

a, b, and c have been defined to be integer variables. Which of the following values make the expression !(a == b) && (c > a) true

!(a == b) means (a!=b)

a = 10, b = 20, c = 15

10!=20 ->True

(15 > 10) ->True

!(a == b) && (c > a) // True and True so it is true

Option c

3.

The scope of the parameter is limited to the method which calls it.

True

4.

int[] a = {0,1,2,3,4,5,6}; // The number of elemnts is 7

System.out.println(a.length); // It print 7

Option b

5.

Initialize all of the elements of a double array a to the same value equal to 1.5.

for(int i=0; i<a.length; i++) // Loop runs from 0 array length

a[i] = 1.5; // Initialize all elements 1.5

Option c

6.

Consider the method castToIntArray that has an array of double type as a formal parameter and returns an array of integers. What is the signature of the method

public int[] castToIntArray(double[] a)

Option e

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