This question is from Principle of Internet Programming(php) subject. Question1
ID: 3908980 • Letter: T
Question
This question is from Principle of Internet Programming(php) subject. Question1 a) [Javascript] Receive number from user input where it must be between 10 and 100, when it is out-of-range force user to re enter.List out every number that is divisible by 2 and 10 from 1 to select number. b) [phplReceive two numbers from HTML form (via GET method),then list out the even numbers and total sum of all even numbers in between them.Error checking need to be included,where starting value must be less than ending value and the ending value must not exceed 100.Explanation / Answer
a)
<!DOCTYPE html>
<html>
<body>
<p>Click the button to demonstrate the prompt box.</p>
<button>Try it</button>
<p id="demo"></p>
<script>
function myFunction() {
while(true){
var number = prompt("Please enter a number between 10 and 100: ");
if(number >= 10 && number <= 100)
break;
alert("Invalid value entered!! Try again...");
}
var text = "The numbers divisible by 2 and 10 are : <br>";
for(var i=1; i <= number; i++) {
if(i % 10 == 0)
text += i + "<br>";
}
document.getElementById("demo").innerHTML = text;
}
</script>
</body>
</html>
b)
function myFunction($digits) {
$num1 = $_GET['num1'];
$num2 = $_GET['num2'];
if($num1 > $num2) {
echo "Starting number cannot be greater than ending number!!";
return;
}
if($num2 > 100) {
echo "Ending number cannot exceed 100!!";
return;
}
$even_sum = 0;
echo "The even numbers between this range are : ";
for($i = $num1; $i <= $num2 ;$i ++) {
if($i % 2 == 0) {
echo $i." ";
$even_sum = $even_sum + $i;
}
}
echo "The sum of even numbers is : ".$even_sum
}
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