Custom Subnet Masks 26 indicates the total number of bits used for the network a
ID: 3903955 • Letter: C
Question
Custom Subnet Masks 26 indicates the total number of bits used for the network and Network Address 148.75.0.0 126 subnetwork portion of the address. All bits remaining belong to the host portion of the address Address class Default subnet mask Custom subnet mask Total number of subnets Total number of host addresses Number of usable addresses Number of bits borrowed 255. 255, 0.0 255.255 . 255.192 1024 64 62 lo Show your work for Problem 3 in the space below Number of Hosts 256 128 64 32 16 84 2 Number of Subnets48 16 32 64 128 256 N Binary values-1286432 /6 8 4 2 ?.12864 3216 8 2 28 128 64 +64 3 2 Observe the total number of -2 numbers to the left of the line to create the custom subnet mask Subtract 2 for the number of usable hosts 2 10 24 subract 2 tor the total number of 2 subnets to get the usable number of 255 14Explanation / Answer
Network Address : 148.75.0.0/26
Equivalent binary representation: 10010100.01001011.00000000.00 000000 has a subnet mask
255.255.255.192 (11111111.11111111.11111111.11 000000) . Since the network address starts with 148, it belongs to class B. The network portion in class B is 16 bits.
The custom subnet mask has additional 10 bits borrowed from host portion to get a total of 26 bits for network portion.
Hence the total numer of bits available for host portion is 16-10= 6 bits.
The additional 10 bits borrowed from host portion are used for subnetting within that network. Therefore the total number of subnets available in that network are 2^10 = 1024.
Under each subnet total number of hosts(unique IP addresses possible) available are 2^6=64. In that 64 IP addresses, one is reserved for subnet address(1 IP address) and one is reserved for broadcast address(1 IP address) for each subnet. Thus number of usable IP addresses for hosts in each subnet is 64-2 =62.
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