Suppose the Name class represents one person\'s name (which may have an arbitrar
ID: 3903549 • Letter: S
Question
Suppose the Name class represents one person's name (which may have an arbitrary number of parts) public class Name implements Comparable { private String [] name-parts; public int compareTo (Name n) [ / here public int hashCode() [ here public boolean equals (Object o) - / here 1. Implement the compareTo method (consider the first part, then if they are identical, move on to the next part). You may make use of String.compareTo ). 2. Implement equalsC.) 3. Implement hashCode () 4. Are your implementations of equals ) and hashCode ) compatible? 5. Can you identify two Names which have the same hash code? Does this matter?Explanation / Answer
public int compareTo(Name n)
{ return n.name_parts.compareTo(this.name_parts);
}
public int hashCode()
{
return this.name_parts.hashCode();
}
yes equals() and hashCode() are equal.
public int equals(Name n)
{ if (n.name_parts.compareTo(this.name_parts) == 0)
return 1;
else return 0;
}
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