The code below reads in a list of 10 words and adds them to a map of string->int

Question

The code below reads in a list of 10 words and adds them to a map of string->int. Add code to print out each word you were given with the number of times it was present in the list.
Hint: You just have to iterate through the map and print out each key/value pair with a space between them and a line break after.

#include <iostream>
#include <map>

using namespace std;

int main()
{
map<string, int> wordCounts;

for(int i = 0; i < 10; i++) {
string word;
cin >> word;
//add 1 to the count for that word
// anything that doesn't exist already
// becomes 0 when we try to read it!
wordCounts[word] = wordCounts[word] + 1;
}

//Do not modify anything on or above the line below this
//YOUR_CODE_BELOW

//YOUR_CODE

//YOUR_CODE_ABOVE
//Do not modify anything on or below the line above this

return 0;
}

Explanation / Answer

#include <iostream>
#include <map>

using namespace std;

int main()
{
    map<string, int> wordCounts;

    for (int i = 0; i < 10; i++) {
        string word;
        cin >> word;
        //add 1 to the count for that word
        // anything that doesn't exist already
        // becomes 0 when we try to read it!
        wordCounts[word] = wordCounts[word] + 1;
    }

    //Do not modify anything on or above the line below this
    //YOUR_CODE_BELOW

    //YOUR_CODE
   map <string, int>::iterator it;
   for(it = wordCounts.begin(); it != wordCounts.end(); it++) {
       cout << it->first << " " << it->second << endl;
   }
    //YOUR_CODE_ABOVE
    //Do not modify anything on or below the line above this

    return 0;
}

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