Each of two long straight parallel wires 8 cm apart carries a current of 75 A .

Question

Each of two long straight parallel wires 8 cm apart carries a current of 75 A. The figure shows a cross section, with the wires running perpendicular to the page and point P lying on the perpendicular bisector of the line between the wires. Find the magnitude and direction of the magnetic field at P when the current in the left-hand wire is out of the page and the current in the right-hand wire is also out of the page.

What is the magnitude of B?

What is the value of By?

Find the magnitude and direction of the magnetic field at P when the current in the left-hand wire is out of the page and the current in the right-hand wire is into the page. What is the magnitude of B?

What is the value of Bz?

Explanation / Answer

B = mu*I/2pi*r

r = 0.08/sqrt(2)

here

B = 2mu*I*cos(45 deg)/2pi*r

= 4*10^-7*75/0.08

= 0.000375 T

=375 uT

direction -y axis

By =-375 uT

b)

same

B = mu*I/2pi*r

r = 0.08/sqrt(2)

here

B = 2mu*I*cos(45 deg)/2pi*r

= 4*10^-7*75/0.08

= 0.000375 T

=375 uT

direction Z axis

Bz =375 uT

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