You have a special lightbulb with a very delicate wire filament. The wire will b

Question

You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.30A , even for an instant. Part A What is the largest root-mean-square current you can run through this bulb? You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.30A , even for an instant. You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.30A , even for an instant. You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.30A , even for an instant. You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.30A , even for an instant. Part A What is the largest root-mean-square current you can run through this bulb? Part A What is the largest root-mean-square current you can run through this bulb? Part A What is the largest root-mean-square current you can run through this bulb? Part A What is the largest root-mean-square current you can run through this bulb? Part A What is the largest root-mean-square current you can run through this bulb? Part A What is the largest root-mean-square current you can run through this bulb? You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.30A , even for an instant. Part A What is the largest root-mean-square current you can run through this bulb?

Explanation / Answer

RMS current is defined as Io (original current) / sqrt(2), or roughly Io * 0.707. If Io is ever above 1.30 A, the bulb will blow. 1.30*0.707 = about 0.9191 amps(answer)

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