Values: [01] 26 Correct answers will be in following ranges: 20-2. 2:00; 5:00 Me
ID: 3901225 • Letter: V
Question
Values:
[01] 26
Correct answers will be in following ranges:
20-2. 2:00; 5:00 MeV
20-3. 2:5, 4:5 kg
Identify X (chemical symbol and atomic mass number) in each of the following decays or reactions: 920F rightarrow X + e- + v- X rightarrow 24He + 58140Ce X + 714N rightarrow 11H + 817O 37Li + 11H rightarrow 24He + X For each answer, type the chemical symbol followed by the atomic mass number (no spaces). For example Na23, not Na 23 or na23 or NA23. Note that these answers are worth 2 points each (like multiple-choice questions), and no retries will be allowed. 90232Th undergoes alpha decay to 88228Ra. Find the energy released in this decay. The atomic mass of 90232Th is 232.038050 u, the atomic mass of 88228Ra is 228.031064 u, and the atomic mass of 24He is 4.002603 u. The fission of 92235U releases 208 MeV of energy, on the average. What mass of 92235U must undergo fission to operate a 1000-MW power plant for one day if the efficiency of the power plant is [01] ________%? The efficiency is defined to be the work output (1000 MJ every second) divided by the heat input (the energy released by the fission).Explanation / Answer
20-1
a) Ne20
b) Nd144
c) He4
d) He4
20-2
Change in mass =(232.098050-228.031064-4.002603)u = 4.383*10^-3 u
1 u of mass releases 931 Mev of energy
Thus energy released in this reaction = 931*0.064383 = 4.080573 Mev
20-3
Energy released by 1 Ur = 208 ev = 3.325*10^-11 J
energy released my 1 mol (238 gm) Ur = 3.325*10^-11*6.63*10^23 J = 2.071*10^12 J
Energy needed = 100MJ per second
Ur neede per second considering efficiency of 1 % = 100*10^6/(0.01*2.071*10^12) = 4.8285*10^-3 gm
Ur neede per day = 4.8285*10^-3 *60*60*24/100 Kg = 4.171 kg
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