ONLY ABC. A square, 30- turn coil 10 cm on a a side with a resistance of o.820 o
ID: 3900232 • Letter: O
Question
ONLY ABC. A square, 30- turn coil 10 cm on a a side with a resistance of o.820 ohms is placed between the poles of a large electromagnet. The electromagnet produces a constant, uniform magnetic field of 0.600 T directed into the page. As suggested by the figure, the field drops sharply to zero at the edges of the magnet. The coild moves to the right at a constant velocity of 2 cm/s. (a) what is the current though the wire coild before the coild reaches the edge of the field, (b) while the coil is leving the field, and (c) after the coil leaves the field?
A square, 30-turn coil 10.0 cm on a side with a resistance of 0.820 Ohm is placed between the poles of a large electromagnet. The electromagnet produces a constant, uniform magnetic field of 0.600T directed into . As suggested by Figure 20-22, the field drops sharply to zero at the edges of the magnet. The coil moves to the right at a constant velocity of 2.00 cm/s. What is the current through the wire coil (a) before the coil reaches the edge of the field, while the coil is leaving the field, and after the coil leaves the field? What is the total charge that flows past a given point in the coil as it leaves the field? Plot the induced current in the loop as a function of the horizontal position of the right side of the current loop. Let the right-hand edge of the magnetic field region be x = 0. Your plot should be in the range of -5.00 cmExplanation / Answer
a)Since no change in flux is there hence no induced voltage so current will be zero.
b)Emf=nBVL where n is the no. of turns,B is magnetic field,L is edge length,V is the velocity
or
E=iR=nBVL
or
i=nBVL/R=43.902 mA
c) After leaving no change in flux is there hence no induced voltage so current will be zero.
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