Please show all work LON-C. X c n Elec... X Black bo X https://s3.lite.msu.edu/r

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Please show all work

LON-C. X c n Elec... X Black bo X https://s3.lite.msu.edu/res/sc/ghlanpied/courses/usclib/hrw8/chapter28/hrw8c28p17.problemit 13 Main Menu Course Contents Course Contents HW 6 An electron with kinetic energy K circles in a plane Notes Bookmark Evaluate M Communicate Print (8c28p17) An electron with kinetic energy 1.94 keVcircles in a plane perpendicular to a uniform magnetic field. The orbit radius is 32.0 cm. Find the speed of the electron. 26.12 10 6m/s 2 Submit Answer Incompatible units. No conversion found between "am/SA2" and the required units. Tries 0/15 Previous Tries Find the magnetic field. Submit Answer Incorrect. Tries 1/15 Previous Tries Find the frequency of circling. (Hz) Submit Answer Tries 0/15 Find the period of the motion. Submit Answer Tries 0/15 This discussion is closed Send Feed S A LTE

Explanation / Answer

a) V= sqrt (2K / m) = sqrt (2 * 1940 * 1.6 * 10^-19 / 9.1 * 10^-31) = 2.612 * 10^ 7 m/s

b) B = mv / rq = (9.1 * 10^-31 * 2.612 * 10^7) / 0.32 * 1.6 * 10^-19 = 4.642 * 10^-4 T

c) v = r * (omega) ; (omega) = 2(pi) * f

v = 2(pi) *r *f

==> f = v / 2(pi) *r = 2.612 * 10^7 / (2* 3.14 * 0.32) = 1.3 * 10^7 Hz.

d) T = 1 / f = 1 / (1.3 * 10^7) = 7.692 * 10^-8 seconds

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