A block of base 10 cm times 10 cm and height 15 cm is kept on an inclined plane.

Question

A block of base 10 cm times 10 cm and height 15 cm is kept on an inclined plane. The coefficient of friction between them is . The inclination theta of this inclined plane from the horizontal plane is gradually increased from 0 degree. Then at theta = 30 degree, the block will start sliding down the plane the block will remain at rest on the plane up to certain degree and then it will topple at theta = 60 degree, the block will start sliding down the plane and continue to do so at higher angles at theta = 60 degree, the block will start sliding down the plane and on further increasing theta, it will topple at certain theta

Explanation / Answer

B is correct

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