Need answer for both part ( 1 and 2), please help. A metal ball having net charg

Question

Need answer for both part ( 1 and 2), please help.

A metal ball having net charge of 5.29 10-6 degree C is thrown out of a window horizontally at a speed of 36 m/s . The window is .it a height of 65.7 in above the ground. A uniform horizontal magnetic field of magnitude of 0.0225 T is perpendicular to the plane of the ball's trajectory. The acceleration of gravity is 9.8 m/s2. Find the magnitude of the magnetic force acting on the ball just before it hits the ground. Answer in units of N Instead of a horizontal magnetic field, there is a vertical magnetic field. Find the magnitude of the magnetic force acting on the ball just before it hits the ground. Answer in units of N

Explanation / Answer

A)

q = 5.29*10^-6 C ==>charge on ball
v = (36,sqr(2*g*h),0) m/s ==> (x,y,z)
components of velocity just before it hits the ground.
B = (0,0,0.0225) T ==> (x,y,z) components of magnetic force.

F = q (vXB) ==>

Fx = 1.115E-5 N
Fy = 1.2549E-5 N
Fz = 0 N

|F| = |q (vXB)|=sqrt(Fx^2+Fy^2+Fz^2) = 1.7E-5 N

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