The figure shows a hollow conducting spherical shell with an inner radius of 8 c

Question

The figure shows a hollow conducting spherical shell with an inner radius of 8 cm and an outer radius of 10 cm. A charge, q, placed at the center of the shell causes an electric field at the inner surface of the shell, Ei, which has a magnitude of 80 N/C and points toward the center of the sphere. Additionally, there is an electric field at the outer surface, Eo, which has a magnitude of 80 N/C and points away from the center of the sphere. Determine the charge ON the spherical shell. Answer is + 1.46

Explanation / Answer

on inner surface

E =KQ/R/R

-80= K*Q/.08/0.08

Qinn = - .08*.08*80/k

net electric field on surface of conductor =0

now on outer surface kQinn/.1/.1 +kq/.01/.01 =0

q=-Qinn

q = .08*.08/(8.89 * 10^(9)

q = 1.46 * 10^(-10)

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