Standing near the edge of a 12m high building. A ball is kicked with a initial v

Question

Standing near the edge of a 12m high building. A ball is kicked with a initial velocity 16m/s at 60 degrees with the horizontal. Negelct air resistance. How high above the the height of the building will the ball reach? What is the speed just before it hits the ground?

Standing near the edge of the roof of a 12 m high building, you kick a ball with an initial speed of vt = 16 m/s at an angle of 60" above the horizontal. Neglecting effects due to air resistance, find: how high above the height of the building the ball rises its speed just before it hits the ground You need to apply the conservation of energy theorem.

Explanation / Answer

let the height be h.

a)let the roof top be reference for potential energy.

then 0.5*m*16^2=0.5*m*(16*cos(60))^2+m*g*h

h=9.79 m

b)let the speed as it hits ground=v

then 0.5*m*16^2=-m*g*12+0.5*m*v^2

v=22.163 m/s

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.