Standard reduction half-cell potentials at 25C Use tabulated standard electrode

Question

Standard reduction half-cell potentials at 25C

Use tabulated standard electrode potentials to calculate the standard cell potential for the reaction occurring in an electrochemical cell at 25 C. (The equation is balanced.)

3Ni2+(aq)+2Cr(s)3Ni(s)+2Cr3+(aq)

Express your answer to two significant figures and include the appropriate units.

Half-reaction E (V) Half-reaction E (V) Au3+(aq)+3eAu(s) 1.50 Fe2+(aq)+2eFe(s) 0.45 Ag+(aq)+eAg(s) 0.80 Cr3+(aq)+eCr2+(aq) 0.50 Fe3+(aq)+3eFe2+(aq) 0.77 Cr3+(aq)+3eCr(s) 0.73 Cu+(aq)+eCu(s) 0.52 Zn2+(aq)+2eZn(s) 0.76 Cu2+(aq)+2eCu(s) 0.34 Mn2+(aq)+2eMn(s) 1.18 2H+(aq)+2eH2(g) 0.00 Al3+(aq)+3eAl(s) 1.66 Fe3+(aq)+3eFe(s) 0.036 Mg2+(aq)+2eMg(s) 2.37 Pb2+(aq)+2ePb(s) 0.13 Na+(aq)+eNa(s) 2.71 Sn2+(aq)+2eSn(s) 0.14 Ca2+(aq)+2eCa(s) 2.76 Ni2+(aq)+2eNi(s) 0.23 Ba2+(aq)+2eBa(s) 2.90 Co2+(aq)+2eCo(s) 0.28 K+(aq)+eK(s) 2.92 Cd2+(aq)+2eCd(s) 0.40 Li+(aq)+eLi(s) 3.04

Explanation / Answer

3Ni2+(aq)+2Cr(s)3Ni(s)+2Cr3+(aq)

E0 Cell = E cathode - E anode

E0 Cell = E Ni+2/NI - E Cr/Cr+3

E0 Cell = 3(-0.23) - 2(-0.73)

E0 Cell = +0.77 V

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