%3Cp%3ETwo%20resistors%20A%20and%20B%20are%2060%2C000%20and%2040%2C000%20%20%26n
ID: 3896701 • Letter: #
Question
%3Cp%3ETwo%20resistors%20A%20and%20B%20are%2060%2C000%20and%2040%2C000%20%20%26nbsp%3B%0A%3Cspan%20class%3D%22finalized_jax%22%3E%5C(%5COmega%5C)%3C%2Fspan%3E%20%26nbsp%3B%20respectively%0Aand%20are%20in%20series%20across%20a%20constant%20power%20supply%20of%20100V.%20A%2010%2C000%0A%26nbsp%3B%26nbsp%3B%20%3Cspan%20class%3D%22finalized_jax%22%3E%5C(%5COmega%5C)%3C%2Fspan%3E%20%26nbsp%3B%0Ais%20connected%20across%20B.%20What%20is%20the%20current%20flowing%20in%20the%20circuit%3F%0AWhat%20amount%20of%20current%20is%20flowing%20in%20each%20of%20the%203%20resistors%3F%0A(please%20show%20all%20your%20work%20clearly).%3C%2Fp%3E%0AExplanation / Answer
A and B are 60,000 and 40,000 (undefined) respectively and are in series across a constant power supply of 100V
A 10,000 (undefined) is connected across B
A and 10000 register is in parallel and other one is in series so
net r = 60000 *10000(70000) +40000
=340000/7 ohm
current =100/net r =7/3400 across B
ACROSS A =1/7 (7/3400) = 1/3400 amp USING current through r1 (one of the parallel reg=(r2/r1+r2)net curr
Across 10000=4/7(7/3400)=4/3400 amp
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