Three long parallel wires are 3.8 c m from one another. (Looking along them, the

Question

Three long parallel wires are 3.8 cm from one another. (Looking along them, they are at three corners of an equilateral triangle.) The current in each wire is 5.10A , but its direction in wire M is opposite to that in wires Nand P (see the figure (Figure 1) ).

Part A

Determine the magnitude of the magnetic force per unit length on wire M due to the other two.

Part B

Determine the angle of the magnetic force per unit length on wire M due to the other two.

Part C

Determine the magnitude of the magnetic force per unit length on wire N due to the other two.

Part D

Determine angle of the magnetic force per unit length on wire N due to the other two.

Part E

Determine the magnitude of the magnetic force per unit length on wire P due to the other two.

Part F

Determine the angle of the magnetic force per unit length on wire P due to the other two.

Explanation / Answer

At A the mag of the other two wires is the same and
F/L =?o*I1*I2/2?L = 2x10^-7.0^2/0.38 = 2.58x10^-5N

So F/L total = 2*2.59x10^-5*cos(30) = 4.47x10^-5N

Direction 90o


AT B Same magnitude as A = 4.47x10^-5T

but direction is 300o


At C Magnitude is the same = 4.47x10^-5N

Direction 240o

i have done the same type of problem substitute the values please rate my answer

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