Three masses are sitting on a 2m beam of wood, which rests on a fulcrum. The fir

Question

Three masses are sitting on a 2m beam of wood, which rests on a fulcrum. The first mass is 2 kg and rests 30 cm to the left of the fulcrum. The second mass is 5 kg and sits 45cm from the left side of the beam. The fulcrum is located at the middle of the beam. The third mass is 6 kg. If the system is in rotational equilibrium where is the third mass located? DRAW OUT A DIAGRAM WITH TO HELP SOLVE WHAT SIDE AND DISTANCE FROM THE FULCRUM THE THIRD MASS IS LOCATED.

PLEASE SHOW ALL WORK AND EXPLAIN! Thanks!

Explanation / Answer

anticlockwise moments about the fulcrum = (2*0.3) + [5*{(2/2)-0.45}] = 3.35 N-m for the rotational equilibrium; anticlockwise moments about the fulcrum = clockwise moments about the fulcrum => clockwise moments about the fulcrum = 3.35 => 6*x = 3.35 => x = 0.56 m from the fulcrum to the right

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