1. The moon orbits the earth at a distance of about 3.84 * 10^8 (m) in a path th
ID: 3893715 • Letter: 1
Question
1. The moon orbits the earth at a distance of about 3.84 * 10^8 (m) in a path that takes 27.3 days to complete. What is the centripetal acceleration of the moon?
2. When a bucket of water is swung in a vertical circle, the water will remain in the bucket if the velocity is kept high enough. If you let the bucket slow down too much the water will spill out. The critical velocity is the slowest velocity necessary to keep the water in the bucket. What is the critical velocity if the formula is: velocity = sqrt r*g, where the radius of your arm swing including the bucket is r, and g is the acceleration of gravity? (Hint: you must measure or estimate the length from your shoulder to the center of the bucket to determine radius)
Please don't post just the formula, I need explanation preferably with the figures given, thank you
Explanation / Answer
a.
the formula for centripetal acceleration is: centripetal acceleration = v^2/r velocity has to be in m/s radius has to be in m radius = 384,000,000 m
T = 27.3 days .
ac = w^2 R = (2pi/T)^2 R is the centripetal acceleration.
T = 2.36E6 sec and R = 3.84E8 meters.
w = 2pi/T is the angular speed of the orbit.
Thus ac = ((2*pi/2.36E6)^2)*3.85E8 = 0.0027191 or 2.71E-3 m/sec^2
it's called centrifical force. It works vertically, horizontally and if get it going fast enough, can even turn it upside down without losing a drop of water. half full, and spin it around and tilt it until it was upside down. The water will not come out if the bucket is spinning fast enough and there is enough space underneath the bucket to force or draw air upward.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.