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1. The moon with no heat transport. The layer model assumes that the temperature

ID: 154778 • Letter: 1

Question

1. The moon with no heat transport. The layer model assumes that the temperature of
the body in space is all the same. This isn't really very accurate, as you know that it's
colder at the poles than it is at the equator. For a bare rock with no atmosphere or ocean,
like the moon, the situation is even worse, because fluids like air and water are how heat
is carried around on the planet. So let's make the other extreme assumption, that there is
no heat transport on a bare rock like the moon. What is the equilibrium temperature of the
surface of the moon, on the equator, at local noon, when the sun is directly overhead?
What is the equilibrium temperature on the dark side of the moon?
Assuming an albedo of 0.3, 360 K. On the dark side, 0 K.
2. A two-layer model. Insert another atmospheric layer into the model, just like the first
one. The layer is transparent to visible light but a blackbody for infrared.
a) Write the energy budgets for both atmospheric layers, for the ground, and for the earth
as a whole, just like we did for the one-layer model.
b) Manipulate the budget for the earth as a whole to obtain the temperature T2 of the top
atmospheric layer, labeled Atmospheric Layer 2 in Figure 3-5. Does this part of the
exercise seem familiar in any way? Does the term skin temperature ring any bells?
c) Insert the value you found for T2 into the energy budget for layer 2, and solve for the
temperature of layer 1 in terms of layer 2. How much bigger is T1 than T2?
d) Now insert the value you found for T1 into the budget for atmospheric layer 1, to
obtain the temperature of the ground, Tground. Is the greenhouse effect stronger or weaker
because of the second layer?

3. Nuclear Winter. Let

Explanation / Answer

!)as albedo is 0.3 it means 70 percent solar energy is trapped in day time , and temerature is 360 K so best we can do it may be mean temp , so apply maximumat noon and minimum at morning and evening by standard deviation or some other thing stats expert can help in this better on the dark side O kevin provide me more details of two layer model

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