1. In this lab we discussed the specific heat in the units cal/g degree C. In st

Question

1. In this lab we discussed the specific heat in the units cal/g degree C. In strict SI units specific heat should be expressed in J/Kg degree C. What is the specific heat of water in these units? (Show and label conversion)

2. In connection with the gas laws we often use the molar specific heat. Express specific heat of water in J/Kmole degree C (show and label conversion)

3. A 100.0Kg rock is dropped from a height of 100.0m into a container of water of mass 10000Kg. If all of the energy is converted into heat, and the heat gained by the container is negligible find the change in temp of water. (Show work)

4.

Explanation / Answer

Specific heat units=cal/g degree C

1 cal=4.184 J

1g = 10^3 kg

using this conversion

1)

Specific Heat of Water = 1cal/g degree C

1cal=4184 J/kg degree C

2)

molar mass of water=18*10^-3 Kg

molar specific heat=4183*10^-3*18=75.312 J/K mole

3)

change in potential energy of rock=increase in thermal energy of water

100*9.8*100=10000*4184*change in Temperature:taking g=9.8 m/s^2

change in Temperature=0.00234 degree C

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