1. A cue stick hits a cue ball with an average force of 23 N for a duration of 0

Question

1. A cue stick hits a cue ball with an average force of 23 N for a duration of 0.026 s. If the mass of the ball is 0.14 kg, how fast is it moving after being struck?

_______m/s

2.   A ball of mass 5.0 kg moving with speed of 2.0 m/s in the +x-direction hits a wall and bounces back with the same speed in the -x-direction. What is the change of momentum of the ball?

magnitude_______kg*m/s

3.   A volleyball is spiked so that its incoming velocity of +4.1 m/s is changed to an outgoing velocity of -20 m/s. The mass of the volleyball is 0.43 kg. What impulse does the player apply to the ball?

______kg*m/s

Explanation / Answer

1. impulse = change of momentum

23 * 0.026 = 0.14* v

v = 4.27 m/s

2. change of momeuntum = mv-(-mu)

= m(u+v)

= 5*(2+2) =

20 kgm/s

3.change of momentum P = mV-(-mu) = m(u+v)

P = 0.43*(4.1+20)

P = 10.363 Kgm/s

4. impulse = change of momentum

Ft = mV-mu

2.3*10^6 * 11 = 7.6*10^7 - mu

mu = 76 *10^6 -2.3*10^6

mu = 7.37 *10^6 kgm/s

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