A proton moves at 5.40 E5 m/s in the horizontal direction. It enters a uniform v

Question

A proton moves at 5.40 E5 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.40 E3 N/C. Ignore any gravitational effects.

(a) Find the time interval required for the proton to travel 6.00 cm horizontally. [ns]

(b) Find its vertical displacement during the time interval in which it travels 6.00 cm horizontally. (Indicate direction with the sign of your answer.) [mm]

(c) Find the horizontal and vertical components of its velocity after it has traveled 6.00 cm horizontally. [ (i) and (j) components km/s]

A proton is projected in the positive x direction into a region of uniform electric field = (-5.20E5) N/C at t = 0. The proton travels 6.20 cm as it comes to rest.

(a) Determine the acceleration of the proton. [magnitude m/s2]

(b) Determine the initial speed of the proton. [magnitude m/s]

(c) Determine the time interval over which the proton comes to rest. [s]

I really need help with these 2 questions! Just need a final answer, little explanation required but please include the numerical work so I can understand and also please follow the units in the [brackets]

Explanation / Answer

Final answers 1.a)1.11*10^-7 s.

b) 5.55*10^-3 m = 5.55 mm

c)Vx=5.4*10^5 m/s

Vy=10^5 m/s

2.a)4.98*10^13 m/s^2

b)2.485*10^6 m/s.

c)0.49*10^-7 s

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