A b of 50 parts contains 5 that are defective. A sample of 10 parts are selected

Question

A b of 50 parts contains 5 that are defective. A sample of 10 parts are selected at random, without replacement. Compute the probability that a sample contains at least four defective parts. Consider the hospital emergency room data given below. Let A denote the event that a visit is to the hospital 4, and let B denote the event that a visit results in the patient leaving without being seen (LWBS). Use the addition rules to calculate the following probabilities. (a) P(A Union B) (b) P(A Union B') (c) P(A' Union B')

Explanation / Answer

Sice there are more than 1 question i am answering the first one only.

The number of ways to select two 10 from 50 is 50C10 and the number of ways to select atleast 4 defective parts from the 5 defective ones is 5C4+5C5. Therefore the probability is (5C4+5C5)/50C10= 6/10272278170= 0.000000000584

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