ysis of a simple circuit, synthesis of a simple circn ce materials: I. Chapter 1

Question

ysis of a simple circuit, synthesis of a simple circn ce materials: I. Chapter 11, textbook 2. Basic Logic Gates, Figure 111 3. LogicWorks web page http://desi 5- windows 4. LogicWorks tutorial example http://www.cs.uregina.ca/Links/class- Exercise 1: Using LogicWorks 5 simulate the circuit below 1.1 Review reference materials above 1.2 Start Windows. 1.3 Start LogicWorks 5 from Windows Menu (All Apps) 1.4 In LogicWorks, lay out the circuit components including the binary switches and the binary probe. 1.5 Apply different inputs to the binary switches and record the circuit responses by observing the value in the binary probe F: build the complete truth table for this circuit. 1.6 Identify the function performed by this circuit. Put the answers to Questions 1.4, 1.5, 1.6 (including the screen shots showing the circuit layout in LogicWorks 5) in to a word processor document and store it as a pdf file Include a preamble (title section) with your name, student number, course number etc. Submit this file on D2L as Lab 1 Report.

Explanation / Answer

Here, the circuit-diagram consists of 3 Inputs ie A,B,C. So, lets draw the Truth Table step by step

For the first AND Gate the TT is given below:-    Here the boolean expression is:- A.B'

For the Second AND Gate the TT is given below:-       Here the boolean expression is:- A'.B

Now the OR Gate results to A'B OR AB', which is infact A XOR B

Similarly when C comes as input to the above expression we get from AND Gate3 = (A XOR B) AND C'

And from AND Gate4 we get NOT(A XOR B) AND C

Finally, taking the OR operation of the above two expression we get:-

((A XOR B) AND C') OR (NOT(A XOR B) AND C)

= (A XOR B XOR C) [Hint:- Taking (A XOR B) as X, we get XC' OR X'C]

So the entire Truth Table for this logic circuit will be:-

Hence this is a FULL-ADDER operation performed by the circuit, whose SUM = A XOR B XOR C

Please let me know in case of any clarifications required. Thanks!

A B B' RES = A AND B' 0 0 1 0 0 1 0 0 1 0 1 1 1 1 0 0

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