Show the transistor count on your schematic. Also show in your test schematic th

Question

Show the transistor count on your schematic. Also show in your test schematic the truth table for the full added ( Sum of products implementation) . USE NO XOR GATES. Appreciate it ! Digital Logic Devices We can see from the e Table 2.7 Truth table for of one column must a cuit is called a half ad We write the eight po Next we figure out th Outputsare 1 in each row. If but no carry, two give You can simul 0 0 0 00 verify your design be We can abstra with the appropriate i a full adder Inputs A B C CarrySum Figure If we want to build a Figure 2.4. Note tha A7 B7 A6 B6 A5 B5

Explanation / Answer

e know the equations for S and COUT from earlier calculations as

S = A B Cin + A BC in + ABCin

Cout = AB + ACin + BCin

We can rewrite the equation for sum as follows.

S = A B Cin + A BC in + ABCin

= Cin (A B + AB) + C in (A B + A B )

Therefore S = CIN XOR (A XOR B)

= Cin (A X-NOR B) + C in (A X-OR B)

= Cin XOR (A XOR B)

Cout is simplified as

COUT = A B + A CIN + B CIN.

COUT = AB + A CIN + B CIN (A + A)

= ABCIN + AB + ACIN + A B CIN

= AB (1 +CIN) + ACIN + A B CIN

= A B + ACIN + A B CIN

= AB + ACIN (B + B ) + ¬ A B CIN

= ABCIN + AB + A B CIN + A B CIN

= AB (CIN + 1) + A B CIN + A B CIN

= AB + A B CIN + A B CIN

= AB + CIN ( AB + A B )

Therefore COUT = AB + CIN (A EX – OR B)

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.