Write and test a C program that lets a user interactively manipulate an array (A

Question

Write and test a C program that lets a user interactively manipulate an array (A) holding 49 integers Commands to the program are integers that should be interpreted as follows 0 Quit the program 1. Fill A with zeroes 2. Generate 49 random integers and store in A. Each integer is greater than 3. 4. 5. or equal to 0 and less than 10. See Program 1 for information about random number generation Output the contents of A, 7 numbers to a line Display the contents of A as a histogram (see example program run) Report the mean, median and standard deviation of contents of A add the following command 6. Report the length and location of the longest sequence of identical integers. (If there are two or more longest sequences, identify the first one.)

Explanation / Answer

#include<stdio.h>
#include <stdlib.h>
#include <math.h>

int main() {
   int m=0,k=0,j=0,n,i,c=0,p,A[49]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49};
   float sv=0,svv;
    printf("Print value of n: ");
    scanf ("%d",&n);
    switch(n){
        case 1:
            break;
        case 2:
            for(i=0;i<49;i++)
            {A[i]=0;
             printf("%d",A[i]);
            }
            break;
        case 3:
        for(i=0;i<49;i++)
         {A[i]= rand()%10;
            printf("%d",A[i]);
         }
       
         break;
        case 4:
        for(i=0;i<49;i++)
        {c=c+1;
        p=c%7;
        printf("%d ",A[i]);
        if(p==0)
        {printf(" ");}
        }
        break;
        case 5:
        for(i=0;i<49;i++)
       {
              printf("%9d%15d       ", i, A[i]);
              for(j = 1; j<= A[i]; j++)
              printf("*");
              printf(" ");
       }
       break;
       case 6:
       for(i=0;i<49;i++)
       {j=j+A[i];}
       k=j/29;
       printf("Mean of all elements = %.2d ", k);
       float temp;
    for(i=48;i>=0;i--)
    {for(j=0;j<=i;j++)
        if(A[j]>=A[j+1])
        {
            temp=A[j];
            A[j]=A[j+1];
            A[j+1]=temp;
        } }
        m=A[24];
        printf("Median of all elements = %.2d ", m);
        for (i = 0; i <49; i++)
    {

        sv = sv + pow((A[i] - k), 2);

    }
    svv = sqrt(sv);
    printf("Standard deviation = %.2f ", svv);

    break;
    }
    return 0;
}

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