Question: What is T in Stack<T>? Is it a string? generic type? stack? integer? P

Question

Question: What is T in Stack<T>?

Is it a string? generic type? stack? integer?

Please explain why :-)

1 public interface Stack { 2 public void push (T value): 3 public T pop(): 4 } 1 public class LinkedStack implements Stack { 2 private Node first = null: 3 public void push(T value) { 4 Node n = new Node (value): 5 n.next = first: 6 first = n: 7 } 8 public T pop() { 9 if (first null) { 10 throw new IllegalAccessException (): 11 } 12 T value = first, value: 13 first = first, next: 14 return value: 15 } 16 } 1 public class FixedArrayStack implements Stack { 2 private T[] items: 3 private int top = 0: 4 public FixedArrayStack(int size) { 5 items = (T[])new Object [size]: 6 } 7 public void push(T value) { 8 items [top] = value: 9 top++: 10 } 11 public T pop() { 12 top--: 13 T value = items [top]: 14 items [top] = null: 15 return value: 16 } 17 } 1 public static main(String [] args) { 2 Stack stack: 3 if (args [0] = 'ARRAY') { 4 stack = new FixedArrayStack (args . length): 5 } else { 6 stack = new LinkedStack (): 7 } 8 for (int i = 0: i

Explanation / Answer

T means type which is mentioned in generic manner. When we declare like this, it can be of any type.

String

main method, line 2 : Stack<String> stack;
which means that the Stack we want to use is of type String.

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