The TAB_BIRTHDAY table consists of every day of the year, from January 1 to Dece

Question

The TAB_BIRTHDAY table consists of every day of the year, from January 1 to December 31, along with a ranking based on how many babies were born in the United States on that date between 1973 and 1999. Rank 1 is the most popular, rank 2 is the next most popular, and so forth.

Create and populate the TAB_BIRTHDAY table by using the following SQL statements.

CREATE TABLE tab_birthday

(BIRTHDAY_MONTH     NUMBER,

BIRTHDAY_DAY       NUMBER,

BIRTHDAY_RANK      NUMBER);

/

INSERT INTO tab_birthday

SELECT * FROM hchen.tab_birthday;

/

COMMIT;

/

SELECT COUNT(*) FROM tab_birthday;

/

Please make sure that there are 366 rows in your TAB_BIRTHDAY table.

You cannot change the definition of the TAB_BIRTHDAY table. You will receive 0 points if you use different table names, column names, or data types.

In the TAB_BIRTHDAY table, you can find that September 16 is the most popular birthday (rank = 1) and February 29 is the least popular birthday (rank = 366). Excluding leap years, December 25 is the least popular birthday (rank = 365).

Write a PL/SQL anonymous block that accepts an integer n (n = 1 or n = 2) from the user input and 1) displays the most popular birthdays along with the ranks for each month if the user input is 1 (n = 1), or 2) displays the least popular birthdays along with the ranks for each month if the user input is 2 (n = 2). Sort your output in ascending order by months.

You will lose 10 points if the title lines are missing in your output.

You will lose 10 points if your output is not in the correct format. For example, you must display the birthdays and ranks for the same month in one line.

Each day-rank pair must be displayed in the DD/RRR format (2-digit day and 3-digit rank) (e.g., 08/012).

You may hard-corded values of months (e.g., FOR idx IN 1..12 LOOP).

If you have hard coded the birthdays or ranks (e.g., DBMS_OUPT.PUT_LINE('1 20/ 240')) in your PL/SQL block, you will receive 0 points.

To avoid complicating issues, you can assume that the user always enters input from keyboard that consists only of the digits 0 through 9 and Enter.

This question can be solved without using cursors.

You will receive 0 points if you submit more than one PL/SQL program.

(This question should take less than 45 minutes to solve.)

Explanation / Answer

step 1: creating the table with respect to data base of required fields.

create table tab_birthday(birthday_month number(2) primary key, birthday_day number(2),birthday_rank number(5));

step 2:write the plsql code for the logic.

$ delimiter party

if(n==1||n==2)

{

select * from tab_birthday order by birthday_month;

}

$ end;

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