.....IN C PROGRAMMING...... .....IN C PROGRAMMING...... .....IN C PROGRAMMING...

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.....IN C PROGRAMMING......

.....IN C PROGRAMMING......

.....IN C PROGRAMMING......

.....IN C PROGRAMMING......

.....IN C PROGRAMMING......

.....IN C PROGRAMMING......

6) Write a valid and compileable for loop that iterates through all the elements of a linked list and counts the number of elements in it. Each element in the list is a "struct Listltem" with a single member nextltem and "mylist" points to the Listltem at head of the list. Use "currentltem" as your iterator variable and store the total count in itemCount. ListItem *currentltem nt itemCount 0 //your for loop starts underneath this commen

Explanation / Answer

Considering it is a a singly linked list, the for loop looks like this:

for(currentItem= mylist;currentItem->nextItem!=NULL;currentItem=curentItem->nextItem)

{

}

in the above code snippet, currentItem is pointing to mylist which is basically head of the linkdlist. It checks until the nextItem is not equal to null it traverses through the list. If completed Code was given could have attached the output also.

Hope this helps!

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