... The two charges Q are fixed at the vertices of an equilateral triangle with

Question

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The two charges Q are fixed at the vertices of an equilateral triangle with sides of length a as shown. What is the work required to move a charge q from the other vertex to the center of the line joining the fixed charges? W = 6kQq/a W = 0 W = 2kQq/a W = 4kQq/a W = kQq/a W= Four charges are at the corners of a square centered at the origin as follows: -9q at (-4a, +3a), -8q at(+4a, +3a), 5q at (+4a, -3a), and 2q at (-4a, -3a). A fifth charge -6q with mass m is placed at the origin and released from rest. Find the ultimate speed when it is a great distance from the origin.

Explanation / Answer

1) Option 3

2) Option 2

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