Linux. Shell script question Thank you Create a shell script that will take 1 ar

Question

Linux. Shell script question

Thank you

Create a shell script that will take 1 argument and will end with a success exit code if the argument is a whole word in the/usr/share/dict/words file, and it will return an error signal of 1 if the argument is not a word on that file. Your script should not produce any output For example, if your script is called isvalid.sh, then you will see the following output (bad is a word in the dictionary, badd is not a word in the dictionary): [you@blue final]$ ./isvalid.sh bad [you@blue final]$ echo $? 0 [you@blue final]$ ./isvalid.sh badd [you@blue final]$ echo $? 1

Explanation / Answer

#!/bin/bash

if grep "$1" "/usr/share/dict/words"
then
    return 0
else
    return 1
fi

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