One if every six children born in the Chicoutimi are of QuebecProvince has Tyros

Question

One if every six children born in the Chicoutimi are of QuebecProvince has Tyrosinemia, a condition that causes severe liverdisease in infancy, commonly resulting in cirrhosis. It is causedby having two copies of a defective allele. Under the assumptionsof Hardy-Weinberg equilibrium, what frequency of the defectiveallele would be required to produce this proportion of afflictednewborns?

Based on this frequency, what proportion of the populationwould be expected to be heteroygotic for this trait??


Thanks!!! Jen

Based on this frequency, what proportion of the populationwould be expected to be heteroygotic for this trait??


Thanks!!! Jen

Explanation / Answer

let p= the proportion recessive and q=the proportiondominant 2. The question states that 1/6 of the population has thedisease and that you must have 2 copies of the allele to have it.This means that the trait is recessive. This means p^2=1/6. Solvingfor p will give you the frequency of thedefective allele. 3. To find the proportion of the population that isheteroygotic for the trait you must solve for q. You can use p+q=1since you already know the proportion for q. Once you find qthe proportion that is heteroygotic= 2pq.

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