One ice skater with a mass of 50 kg pushes a stationary skater with mass of 70 k

Question

One ice skater with a mass of 50 kg pushes a stationary skater with mass of 70 kg. After the first skater pushes the second skater his velocity is 1m/s.
What is the second skaters final velocity and magnitude?
If the push lasted one second what is the force the first skater put on the second skater?

One ice skater with a mass of 50 kg pushes a stationary skater with mass of 70 kg. After the first skater pushes the second skater his velocity is 1m/s.
What is the second skaters final velocity and magnitude?
If the push lasted one second what is the force the first skater put on the second skater?


What is the second skaters final velocity and magnitude?
If the push lasted one second what is the force the first skater put on the second skater?

Explanation / Answer

m1 = 50 Kg , m2 = 70 Kg

v1 = 1 m/s , v2 = ?

a )

using conservation of momentum

m1 v1 + m2 v2 = 0

50 X (-1) + 70 + v2 = 0

-50 + 70 v2 = 0

v2 X 70 = 50

v2 = 50 / 70

v2 = 0.714 m/s

b)

force = impulse / time

time = 1 second

impulse P2 = m2 v2

P2 = 70 X 0.714

P2 = 49.98 Kg.m/s

impulse P1 = m1 v1

P1 = 50 X(-1)

P1 = - 50 Kg.m/s

force F = total impulse / time

F = P2 - P1 / t

F = P2 - P1 / 1

F = 49.98 + 50 / 1

F = 100 N

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.