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Processes 0,1,2,3,4,5,6 are executing concurrently. Process 3, 4, 5, and 6 must

ID: 3831736 • Letter: P

Question

Processes 0,1,2,3,4,5,6 are executing concurrently.
Process 3, 4, 5, and 6 must start their execution after the execution of Process 0, 1,
and 2 ends.
There is no enforcement of order between the executions of Process 3, 4, 5, and 6.
There is no enforcement of order between the executions of Process 0, 1, and 2.
Implement the required synchronization using a minimum number of binary semaphores. Give
the initial values of each semaphore.

what it be the clutcome of replacing in the i wder oodet Deadlock would reader Count --oo ilsen v ito ount 0) then V (mutex) EXTRA CREDIT OPTIONAL (6 points) execution of Process o. Processos 3, 4. 5. are executing concurrently execution after the Processo. Process 3. Process 4, Process 5 Process 6 start their and Process 1 and Process 2 ends A. and Process 2 There is no enforcement of order between the executions of Proc Processi Give the initial There is no enforcement of order between the executions of proc hores Implement the required synchronization using a minimum number of binary value of each semaphore. P0 P4 25 Nov 08 19 41

Explanation / Answer

Solution:

So initially the value of semaphores a, b, c, and d will be set to 0.

par begin

begin P0: par begin V(a), V(b), V(c), par end, end;

begin: P(a), end;

begin P(b), end;

begin P(c), end;

begin: par begin V(a), V(b), V(c), V(d), par end, end;

par end

In the above given sequence 4 semaphores has been used and that is a minimum number in order to provide synchronization between the processes.

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