PLEASE CODE IN PYTHON Part V: diagonal winner(board) This function scans the ent

Question

PLEASE CODE IN PYTHON

Part V: diagonal winner(board)

This function scans the entire game board passed as an argument and returns one of three values:

• 1 if player 1 has placed four consecutive X’s in a diagonal somewhere in the board

• 2 if player 2 has placed four consecutive O’s in a diagonal somewhere in the board

• 0 (zero) if neither player has placed four consecutive pieces in a diagonal somewhere in the board

Under no circumstances is the function permitted to make a change to board.

Note that diagonals can run lower-left-to-upper-right and upper-left-to-lower-right, as shown in the examples below:

...... : ......

...... : ......

....X. : ......

...XO. : .X.O..

..XOX. : .XXO..

.XOXO. : .OXX..

OOXOOX : OOOXXO

PROVIDED BELOW IS THE BOARD CLASS

Explanation / Answer

# PART V
# Determines if a player has won the game by placing four pieces in a diagonal.
# Returns 1 if player 1 has won the game by placing four X's diagonally.
# Returns 2 if player 2 has won the game by placing four O's diagonally.
# Returns 0 if no one has won yet by placing pieces in this manner.
# This function must not modify the contents of the game board.
def diagonal_winner(board):
for i in range(3, board._num_rows):
count1 = 0
count2 = 0
for j in range(0, i+1):
if i == j and board._slots[j][j] == 'X':
count1 += 1
count2 = 0
elif i == j and board._slots[j][j] == 'O':
count2 += 1
count1 = 0
if count1 == 4 and count2 == 0:
return 1
elif count2 == 4 and count1 == 0:
return 2
  
n = board._num_rows
for i in range(3, board._num_rows):
count1 = 0
count2 = 0
for j in range(0, i+1):
if (n-i-1) == j and board._slots[j][j] == 'X':
count1 += 1
count2 = 0
elif (n-1-1) == j and board._slots[j][j] == 'O':
count2 += 1
count1 = 0
if count1 == 4 and count2 == 0:
return 1
elif count2 == 4 and count1 == 0:
return 2
return 0

# pastebin code link: https://pastebin.com/1PfnjKTD

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