Problem 2.0 Part A (0 points) Consider n 1 Gbit DRAM chip organized as 16 millio
ID: 3827321 • Letter: P
Question
Explanation / Answer
part-A ans::
-->No. of columns = square_root (1G = 230) = 215 = 32K
-->Column_decoder required (n to m) = 15k to 32K
-->Type of mux_required (n to m) 32K/64 = 512 to 1 mux
-->No. of muxes required = 64 muxes
-->No. of address lines in column number = 15
-->number of address lines in column offset 9
part-B ans::
-->Word_address lines for memory system = 27
-->Chips needed in one bank = 16 bytes/word / 8 bytes/chip = 2 chips
-->Banks for memory system = 128M / 16M = 8 banks/sys
-->Memory decoder required (n to m) = 3 to 8
-->DRAM chips required = 2 chips/bank x 8 banks = 16 chip
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.