Problem 2. PREVIEW ONLY - ANSWERS NOT RECORDED (1 point) When air expands adiaba

Question

Problem 2. PREVIEW ONLY - ANSWERS NOT RECORDED (1 point) When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equatiowhere C is a constant. Suppose that at a certain instant the volume is 460 cubic centimeters, and the pressure is 89 kPa and is decreasing at a rate of 8 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant? Rate 534.122 (Pa stands for Pascal- it is equivalent to one Newton (meter squared); kPa is a kiloPascal or 1000 Pascals.) cm3/min preview answers Entered Answer Preview 122 -534.122

Explanation / Answer

solution:

dV/dt=-[(dP/dt)*V/(1.4*P)]

=-[-8*460/1.4*89]

=+29.53 cc/sec=29 cc/sec(rounding of)   

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